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**Extra resources for Algebra for College Students (5th Edition) (MathXL Tutorials on CD Series)**

**Example text**

5͑9r͒ 42. Ϫ4 ϩ ͑12 ϩ 8͒ (associative property) 43. 5x ϩ 9y (associative property) 44. Ϫ5 и 7 (commutative property) 45. 1 и 7 (commutative property) 46. Ϫ12x ϩ 0 (identity property) 47. Ϫ 1 1 ty ϩ ty 4 4 (identity property) 48. Ϫ (inverse property) 49. 8͑Ϫ4 ϩ x͒ ͩ ͪ 9 8 Ϫ 8 9 (inverse property) 50. 3͑x Ϫ y ϩ z͒ (distributive property) 51. 875x ϩ 9y Ϫ 88z͒ (distributive property) 52. 0͑35t 2 Ϫ 8t ϩ 12͒ (multiplication property of 0) (multiplication property of 0) 53. Give an “everyday” example of a commutative operation and of one that is not commutative.

18͑14,000 ϩ t͒ 49. 45x 50. 48x 51. A student tried to solve the equation 8x 7x by dividing each side by x, obtaining 8 7. He gave the solution set as ͞0. Why is this incorrect? 52. Explain the distinction between a conditional equation, an identity, and a contradiction. Decide whether each equation is conditional, an identity, or a contradiction. Give the solution set. See Example 5. 53. Ϫ2p ϩ 5p Ϫ 9 3͑ p Ϫ 4͒ Ϫ 5 54. Ϫ6k ϩ 2k Ϫ 11 Ϫ2͑2k Ϫ 3͒ ϩ 4 55. 6x ϩ 2͑x Ϫ 2͒ 9x ϩ 4 56. Ϫ4͑x ϩ 2͒ Ϫ3͑x ϩ 5͒ Ϫ x 57.

See Chapter 6. An Addison-Wesley product. Copyright © 2004 Pearson Education, Inc. 2 Formulas 59 One way to begin is to use the distributive property on the right side of the equation to get P 2L ϩ 2W, which we would then solve as in Example 1. Another way to begin is to divide by the coefficient 2. P 2͑L ϩ W͒ P LϩW 2 P ϪLW 2 or W Divide by 2. P ϪL 2 Subtract L. We can show that this result is equivalent to our result in Example 1 by multiplying L by 22 . P 2 2 2 Ϫ ͑L͒ W 2 1, so L 2 ͑L͒.